2.6x^2+3.4-5=0

Solution for 2.6x^2+3.4-5=0 equation:

2.6x^2+3.4-5=0

We add all the numbers together, and all the variables

2.6x^2-1.6=0

a = 2.6; b = 0; c = -1.6;
Δ = b2-4ac
Δ = 02-4·2.6·(-1.6)
Δ = 16.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{16.64}}{2*2.6}=\frac{0-\sqrt{16.64}}{5.2}
=-\frac{\sqrt{}}{5.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{16.64}}{2*2.6}=\frac{0+\sqrt{16.64}}{5.2}
=\frac{\sqrt{}}{5.2}
$